Problem hidden
|This problem was hidden by Editorial Board member probably because it has incorrect language|version or invalid test data, or description of the problem is not clear.|

ABR201B - Минимум утга

n натурал тоо ба a1, …, an бодит тоонууд өгөгдөв. min(a1, …, an)-г ол.

Input

n натурал тоо ба a1, …, an бодит тоонууд хоорондоо зай, эсвэл мөр шилжүүлэх тэмдэгтээр тусгаарлагдан өгөгдөнө.

Output

min(a1, …, an)-г таслалаас хойш нэг оронгийн нарийвчлалтайгаар хэвлэнэ

Example

Input:
5
19.21 17.03 20.06 -500 17.17

Output:
-500.0

Нэмсэн:sw40
Огноо:2008-01-15
Хугацааны хязгаарлалт:1s
Эх кодын хэмжээний хязгаарлалт:50000B
Memory limit:1536MB
Cluster: Cube (Intel G860)
Програмчлалын хэлүүд:ADA95 ASM32 GAWK BASH BF C CSHARP C++ 4.3.2 CPP C99 CLPS CLOJURE LISP sbcl LISP clisp D FSHARP FORTRAN GO HASK ICON ICK JAVA LUA NEM NICE OCAML PAS-GPC PAS-FPC PERL PHP PIKE PRLG-swi PYTHON PYTHON3 RUBY SCALA SCM guile SCM qobi SED ST TCL TEXT WHITESPACE
Эх сурвалж:Абрамов С. А.

hide comments
2023-10-25 08:51:04
#include<stdio.h>
main(){
int n,i;
float a,k=0;
scanf("%d",&n);
for(i=1;i<=n;i++){
scanf("%f",&a);
if(a<k)
k=a;
}
printf("%.1f",k);
return 0;
}
spoj muu pisda amrhan bdcood baihad buruu hariult gek shajjin




2023-02-10 13:11:59
#include <stdlib.h>

int main() {
int n = 0;
float a, b;
scanf("%d",&n);
scanf("%f",&a);
for (int i = 0; i < n - 1; i++)
{
scanf("%f",&b);
if (b < a)
{
a = b;
}
}

printf("%.1f",a);

return 0;
}
2018-03-05 16:20:15
#include<stdio.h>
#include<stdlib.h>
#include<math.h>
int main()
{
float a[1000],min;
int n,i;
min=a[1];
scanf("%d",&n);
for(i=1;i<=n;i++)
scanf("%f",&a[i]);
for(i=1;i<=n;i++)
if(a[i]<min)
min=a[i];
printf("%.1f",min);
}

enend ymr aldaa bgaa ym
2013-04-19 13:17:45 Iderbat
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main(){
int n;
double b,y;
scanf("%d", &n);
scanf("%lf", &y);
b=y;
n--;
while(n--){
scanf("%lf", &y);
if(b>y)
b=y;


}
printf("%.1lf\n",b);
system("pause");
return 0;
}




2012-04-25 06:02:41 gonchigsvm
chdhgui cbn
2011-11-16 06:23:38 els1
choijilbuu! ehelj a[1]ee asuugaach
2011-11-06 13:38:07 choijilbuu
#include<stdio.h>
float a[1000],min;
int n,i;
main()
{ min=a[1];
scanf("%d",&n);
for(i=1;i<=n;i=i+1)
scanf("%f",&a[i]);
for(i=1;i<=n;i=i+1)
if(a[i]<min) min=a[i];
printf("%.1f",min);
scanf("%f");
} end ymar aldaa bna haraad uguuch
2011-03-01 03:39:53 dashbaljin96
arai ch de
2011-01-06 11:19:16 Undram
eniig bodood ogooch
© Spoj.com. All Rights Reserved. Spoj uses Sphere Engine™ © by Sphere Research Labs.