YODANESS - Yodaness Level
Yoda is the wisest, and perhaps the most powerful Jedi of his time. Yoda is a mysterious figure and he has many oddities. One of them is that Yoda often changes the order of words in the sentence. For example, one of such phrases is "Or I will help you not." Let's call the yodaness level of any statement the number of pairs of words that changed their order, as to the order in which they were supposed to go in a normal statement. Write a program that determines the yodaness level of different statement of Yoda.
Input
The first line of input contains the number t - the number of tests. Next comes the description of t tests. Each test consists of three rows. The first line of the test contains an integer n - number of words in the statement. The next line contains n words separated by spaces - the statement as Yoda says it. The next line is n words separated by spaces - the same statement as it should be said normally. All the words in the statement are different and consist of small Latin letters.
Constraints
1 ≤ t ≤ 10
1 ≤ n ≤ 30000
the length of each word does not exceed 20 characters
Output
For each test print the yodaness level of the statement.
Example
Input: 2 6 in the force strong you are you are strong in the force 6 or i will help you not or i will not help you Output: 11 2
hide comments
ishraaq_56789:
2021-09-22 05:44:23
To the author of the problem, wy is brute force not passing? |
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sicho_mohit:
2021-08-03 15:02:45
First please try this https://www.spoj.com/problems/INVCNT/, then try to do this one. |
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Rafail Loizou:
2021-05-09 22:34:42
@punkfaiz the numbers work correctly for the example that you give just a heads up to everyone else this is not the example input. The example input would be this one:
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punkfaiz:
2020-08-20 11:06:39
1 2 3 4 5 6
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pandey101299:
2020-07-16 14:41:20
similar to inversion count solved using BIT |
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the_pythor:
2020-05-15 09:20:29
This question is the same as "count the number of smaller elements in the right". It took me a while to figure it out. Problem statement should have been more clear. Last edit: 2020-05-15 10:14:06 |
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coolio_1:
2020-03-09 17:22:33
AC in 1 go using BIT |
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harshil nori:
2019-12-04 11:07:22
Solved using merge sort and counting total inverted elements. Good problem. |
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codefresher:
2019-11-22 23:03:47
AC in one go....solved using merge sort tree...
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purplecs:
2019-11-14 07:38:11
easy one |
Added by: | Spooky |
Date: | 2010-03-09 |
Time limit: | 1s |
Source limit: | 50000B |
Memory limit: | 1536MB |
Cluster: | Cube (Intel G860) |
Languages: | All except: NODEJS OBJC PERL6 SQLITE VB.NET |
Resource: | Advancement Spring 2010, http://sevolymp.uuuq.com/ |