In this problem you will be given a half-circle. The half-circle’s radius is r. You can take any point A on the half-circle and draw 2 lines from the point to the two sides of the diameter(AB and AC). Let the sum of square of one line’s length and the other line’s length is s

Like in the figure s = AB² + AC. And BC = 2r.

Now given r you have to find the maximum value of s. That is you have to find point A such that AB² + AC is maximum.

Input

First line of the test case will be the number of test case T (1 ≤ T ≤ 1000). Then T lines follows. On each line you will find a integer number r (1 ≤ r ≤ 1000000); each representing the radius of the half-circle.

Output

For each input line, print a line containing "Case I: ", where I is the test case number and the maximum value of s. Print 2 digit after decimal (Errors should be less then .01).

Example

Sample Input:
1
1

Sample Output:
Case 1: 4.25

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	mohit_010: 2021-11-16 11:41:02 AC AFTER 5 WA JUST SIMPLE NO NEED TO TAKE DOUBLE OR FLOAT USE LONG LONG INT
	Waseem Ahmed: 2021-07-04 13:30:45 Simple one line answer. Not a SPOJ level problem. Disheartened. Hint : Read comments from users "carefully". Especially one user. [NG]: You've been banging for half an hour to get AC in this "simple" problem, then you're whining about how disappointing it was -- like in every other one you solved. Try a problem with less than 5000 solvers sometime, then you'll be qualified to speak of this "SPOJ level" mystery that you keep referring to. Last edit: 2021-07-04 20:42:34
	varuntumbe: 2020-10-18 08:07:40 can i some one tell me why it works for double and not for float.
	imposter_1729: 2020-07-23 15:16:20 try making 180 degree.. and for the second line look at the given sample test case!!!
	ayush_12349: 2020-06-30 13:20:26 In CPP, by default, big numbers will be printed in an "e" format. So, make sure that you do this to match the output format : cout<<fixed; cout<<setprecision(2);
	this_variable: 2020-05-29 17:11:28 Java Bois be careful with this one! :-)
	rohit_world: 2020-05-21 10:12:08 Try long double. The value is fixed for AC. Try to find it. Use iomanip for setting precision and fixed for normal format. Last edit: 2020-05-21 10:12:35
	rohit7ks: 2019-12-27 13:02:29 Use joseph louis theorem, AC in one go
	Saurav Singhi: 2019-10-12 02:34:29 spoiler alert for java. 1 WA for not remembering java's default typecasting during evaluation of regular expressions.
	sanket17: 2019-07-10 10:39:04 if you got the logic then use of double ,float not required Last edit: 2019-07-10 10:40:43